CHEMH9GP [CHENMKO]
暂无描述;型号: | CHEMH9GP |
厂家: | CHENMKO ENTERPRISE CO. LTD. |
描述: | 暂无描述 晶体 晶体管 |
文件: | 总3页 (文件大小:78K) |
中文: | 中文翻译 | 下载: | 下载PDF数据表文档文件 |
CHENMKO ENTERPRISE CO.,LTD
CHEMH9PT
SURFACE MOUNT
NPN Digital Silicon Transistor
VOLTAGE 50 Volts CURRENT 70 mAmpere
APPLICATION
* Switching circuit, Inverter, Interface circuit, Driver circuit.
FEATURE
* Small surface mounting type. (SOT-563)
* High current gain.
SOT-563
* Suitable for high packing density.
* Low colloector-emitter saturation.
* High saturation current capability.
* two CHDTC114Y chips in one package.
* Built in bias resistor(R1=10kΩ, Typ. )
(1)
(5)
(4)
0.50
1.5~1.7
0.50
0.9~1.1
(3)
0.15~0.3
MARKING
1.1~1.3
*H9
0.5~0.6
0.09~0.18
3
4
1
6
1.5~1.7
CIRCUIT
R1 R2
R2
R1
SOT-563
Dimensions in millimeters
LIMITING VALUES
In accordance with the Absolute Maximum Rating System (IEC 60134).
SYMBOL PARAMETER CONDITIONS
Supply voltage
MIN.
MAX.
UNIT
VCC
−
50
V
V
VIN
Input voltage
-6
−
+40
70
IO
DC Output current
mA
−
IC(Max.)
PTOT
100
150
Tamb ≤ 25 OC, Note 1
−
Total power dissipation
Storage temperature
mW
OC
TSTG
−55
+150
OC
−
TJ
Junction temperature
150
Note
1. Transistor mounted on an FR4 printed-circuit board.
2004-07
RATING CHARACTERISTIC ( CHEMH9PT )
CHARACTERISTICS
amb = 25 °C unless otherwise speciÞed.
SYMBOL PARAMETER
Input off voltage
T
CONDITIONS
MIN.
0.3
TYP.
MAX.
UNIT
−
−
−
VIoff)
IO=100uA; VCC=5.0V
IO=1mA; VO=0.3V
IO=5mA; II=0.25mA
V
V
V
VI(on)
1.4
Input on voltage
−
VO(on)
II
Output voltage
Input current
−
0.1
−
0.3
0.88
0.5
−
−
VI=5V
mA
uA
IC(off)
hFE
Output current
DC current gain
Input resistor
Resistor ratio
VI=0V; VCC=50V
IO=5mA; VO=5.0V
−
−
68
7.0
3.7
−
−
R1
10
4.7
250
13
5.7
−
KΩ
R2/R1
IE=-5mA, VCE=10.0V
f =100MHz
MHz
f T
Transition frequency
Note
1.Pulse test: tp≤300uS; δ≤0.02.
RATING CHARACTERISTIC CURVES ( CHEMH9PT )
Typical Electrical Characteristics
Fig.1 Input voltage vs. output current
Fig.2 Output current vs. input voltage
(ON characteristics)
(OFF characteristics)
10m
100
50
VO
=0.3V
VCC=5V
5m
2m
1m
20
O
500
10
5
=-
Ta 40 C
25OC
O
200
=
100OC
Ta 100 C
25OC
100
50
-40OC
2
1
20
10
5
500m
200m
100m
2
1
100
200
500 1m
2m
5m 10m 20m 50m 100m
0
0.5
1.0
1.5
2.0
2.5
3.0
OUTPUT CURRENT : I (A)
O
INPUT VOLTAGE : VI(off) (V)
Fig.3 DC current gain vs. output
Fig.4 Output voltage vs. output
current
current
1k
1
VO
=5V
lO/lI=20
500m
500
200
Ta=100OC
25OC
Ta=100OC
25OC
200m
-40OC
-40OC
100m
50m
100
50
20
20m
10m
5m
10
5
2
1
2m
1m
100 200 500 1m 2m 5m 10m 20m 50m100m
100
200
500 1m
2m
5m 10m 20m 50m 100m
OUTPUT CURRENT : I (A)
O
OUTPUT CURRENT : I (A)
O
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